-2n^2-4n=2

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Solution for -2n^2-4n=2 equation: 



-2n^2-4n=2

We move all terms to the left:

-2n^2-4n-(2)=0

a = -2; b = -4; c = -2;
Δ = b2-4ac
Δ = -42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{4}{-4}=-1$

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